3(2x+4)=4[3x-(7-x)]

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Solution for 3(2x+4)=4[3x-(7-x)] equation:


Simplifying
3(2x + 4) = 4[3x + -1(7 + -1x)]

Reorder the terms:
3(4 + 2x) = 4[3x + -1(7 + -1x)]
(4 * 3 + 2x * 3) = 4[3x + -1(7 + -1x)]
(12 + 6x) = 4[3x + -1(7 + -1x)]
12 + 6x = 4[3x + (7 * -1 + -1x * -1)]
12 + 6x = 4[3x + (-7 + 1x)]

Reorder the terms:
12 + 6x = 4[-7 + 3x + 1x]

Combine like terms: 3x + 1x = 4x
12 + 6x = 4[-7 + 4x]
12 + 6x = [-7 * 4 + 4x * 4]
12 + 6x = [-28 + 16x]

Solving
12 + 6x = -28 + 16x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-16x' to each side of the equation.
12 + 6x + -16x = -28 + 16x + -16x

Combine like terms: 6x + -16x = -10x
12 + -10x = -28 + 16x + -16x

Combine like terms: 16x + -16x = 0
12 + -10x = -28 + 0
12 + -10x = -28

Add '-12' to each side of the equation.
12 + -12 + -10x = -28 + -12

Combine like terms: 12 + -12 = 0
0 + -10x = -28 + -12
-10x = -28 + -12

Combine like terms: -28 + -12 = -40
-10x = -40

Divide each side by '-10'.
x = 4

Simplifying
x = 4

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